Among the following,the most reactive towards | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of haloalkanes with alcoholic $KOH$ proceeds via the $E2$ elimination mechanism.In $CH_3CH_2CH_2Br$ (a primary alkyl halide),the pres

Vedclass · Accepted Answer

$CH_3CH_2CH_2Br$

Vedclass · Answer

(D) The reaction of haloalkanes with alcoholic $KOH$ proceeds via the $E2$ elimination mechanism.In $CH_3CH_2CH_2Br$ (a primary alkyl halide),the presence of the alkyl group provides a $+I$ effect,which facilitates the elimination of the leaving group.$CH_2=CHBr$ is a vinyl halide where the $C-X$ bond has partial double bond character,making it very unreactive towards elimination.$CH_3COCH_2CH_2Br$ contains an electron-withdrawing $-CO$ group ($-I$ effect),which destabilizes the transition state for elimination compared to a simple alkyl halide.Comparing $CH_3CH_2Br$ and $CH_3CH_2CH_2Br$,the latter has a slightly higher $+I$ effect,making it more reactive in this context.$CH_3CH_2CH_2Br + KOH \xrightarrow{	ext{alc.}} CH_3CH=CH_2 + KBr + H_2O$

Among the following,the most reactive towards alcoholic $KOH$ is:

Similar Questions

$C_4H_9Cl$ (Optically Active Compound $A$) $\xrightarrow[DMSO]{NaCN}$ $(R)-2-$methylbutanenitrile; Identify compound $A$?

Which one of the following has the highest boiling point?

Assertion $(A)$: $S_N1$ hydrolysis of optically active $2-$bromooctane results in the formation of $(\pm)-$octan$-2-$ol.
Reason $(R)$: The reaction proceeds through a planar carbocation which can be attacked by the nucleophile from either side.
The correct answer is

For a given alkyl group,the densities of the halides follow the order:

The reaction of $C_6H_5CH=CHCH_3$ with $HBr$ produces

Vedclass Test Series

Exam Paper Generator

Online Exam Module